A metallic rod of mass per unit length 0.5kg m ^ - 1 is lying...

A metallic rod of mass per unit length

0.5kg{m}^{- 1}

is lying horizontally on a smooth inclined plane which makes an angle

{30}^{o}

with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction

0 . 25T

is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is A metallic rod of mass per unit length 0.5kg m ^ - 1 is lying horizontally on a smooth inclined plane which makes an

A metallic rod of mass per unit length 0.5kg m ^ - 1 is lying horizontally on a smooth inclined plane which makes an

Options

A $14 . 76A$
B $5 . 98A$
C $7 . 14A$
D $11 . 32A$

Correct answer

D. $11 . 32A$

Step-by-step solution

For equilibrium of conductor

A metallic rod of mass per unit length 0.5kg m ^ - 1 is lying horizontally on a smooth inclined plane which makes an
$ilBcos \theta = mgsin \theta$

$i = \dfrac{mg}{lB}tan \theta = \left(\dfrac{m}{l}\right)\dfrac{gtan \theta}{B}$

$i = 0.5 \times \dfrac{9.8}{0.25} \times \dfrac{1}{\sqrt{3}} = 11.3A .$

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