A square current carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force on one arm of the loop is F , the net force on the remaining three arms of the loop is

Step-by-step solution

When a current carrying loop is placed in a magnetic field, the coil experiences a torque given by = NBiA . Torque is maximum when =90^ , i. e., the plane of the coil is parallel to the field _ = NBiA Forces F ₁ and F ₂ acting on the coil are equal in magnitude and opposite in direction. As the forces F ₁ and F ₂ have the same line of action, their resultant effect on the coil is zero. The two forces F ₃ and F ₄ are equal in magnitude and opposite in direction. As the two forces have different lines of action, they