A submarine is designed to withstand an absolute pressure of 100 atm. How deep can it go below the water surface ? (Consider the density of water = 1000 kg m ⁻³ , 1 atm = 1 10⁵ Pa and gravitational acceleration g = 10 m/s ^2 )

Step-by-step solution

The absolute pressure at a depth h below the water surface is given by P = P₀ + g h , where P₀ is the atmospheric pressure. Given: P = 100 atm = 100 10^5 Pa P₀ = 1 atm = 1 10^5 Pa = 1000 kg m ⁻³ g = 10 m/s ^2 Substituting the values into the equation: 100 10^5 = 1 10^5 + 1000 10 h 99 10^5 = 10^4 h h = 99 10^5 10^4 h = 990 m Answer: 990 m