An ideal fluid is flowing in a non-uniform cross-sectional tube X Y (as shown in the figure) from end X to end Y . If K₁ and K₂ are the kinetic energy per unit volume of the fluid at X and Y respectively, then the correct option is :

Step-by-step solution

According to Bernoulli's principle, Kinetic energy per unit volume + Potential energy per unit volume + Pressure = Constant 1 2 V^2+ g h+P= constant Apply Bernoulli's principle at point X and Y , P+K₁+ g(0)=P+K₂+ g( ~h )K₁=K₂+ g hK₁ ₂