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NEET 2011
Exam
NEET
Year
2011
Subject
Physics
Chapter
Motion in Two Dimensions

NEET 2011 · Physics · Motion in Two Dimensions

A particle moves in a circle of radius 5 ~cm with constant speed...

A particle moves in a circle of radius 5 cm5 \mathrm{~cm} with constant speed and time period 0.2πs0.2 \pi \mathrm{s}. The acceleration of the particle is

Options

  1. A25 m/s225 \mathrm{~m} / \mathrm{s}^2
  2. B36 m/s236 \mathrm{~m} / \mathrm{s}^2
  3. C5 m/s25 \mathrm{~m} / \mathrm{s}^2
  4. D15 m/s215 \mathrm{~m} / \mathrm{s}^2

Correct answer

C. 5 m/s25 \mathrm{~m} / \mathrm{s}^2

Step-by-step solution

Given, r=5 cm=5×10−2 mr=5 \mathrm{~cm}=5 \times 10^{-2} \mathrm{~m} and T=0.2πsT=0.2 \pi \mathrm{s} We know that acceleration a=rω2=4π2T2r=4×π2×5×10−2(0.2π)2=5 ms−2\begin{aligned}a & =r \omega^2 \\ & =\frac{4 \pi^2}{T^2}r \\ & =\frac{4 \times \pi^2 \times 5 \times 10^{-2}}{(0.2 \pi)^2}=5 \mathrm{~ms}^{-2} \end{aligned}
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