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NEET2019PhysicsMotion in Two DimensionsActual

A particle starting from rest, moves in a circle of radius ' r '. It attains a velocity of v ₀ ~m / s in the n ^ th round. Its angular acceleration will be

Options

  1. Av₀ n rad / s ^2
  2. Bv₀^2 2 n r^2 rad / s ^2
  3. Cv₀^2 4 n r^2 rad / s ^2
  4. Dv₀^2 4 n r rad / s ^2

Correct answer

C. v₀^2 4 n r^2 rad / s ^2

Step-by-step solution

From third equation of motion for circular motion ^2- ₀^2=2 where, = final angular velocity of particle ₀= initial angular velocity = angular acceleration and = angular displacement Here, = v ₀ r rad / s (where, r radius of the circle) ₀=0 (initially particle is at rest) =2 n (for n rounds) Substituting these values in Eq. (i), we get ( v ₀ r )^2-0=2 (2 n ) = v ₀^2 4 nr ^2 rad / s ^2

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