NEET2005PhysicsMotion in Two DimensionsActual
A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone?
Options
- A^2 ~ms ⁻² and direction along the radius towards the centre
- B^2 ~ms ⁻² and direction along the radius away from the centre
- C^2 ~ms ⁻² and direction along the tangent to the circle
- D^2 / 4 ~ms ⁻² and direction along the radius towards the centre
Correct answer
A. ^2 ~ms ⁻² and direction along the radius towards the centre
Step-by-step solution
(a= v^2 r = ^2 r=4 ^2 n^2 r=4 ^2 ( 22 44 )^2 1= ^2 ~m / s ^2 ) and its direction is always along the radius and towards the centre.