A particle moves along a circle ( 20 ) m with constant tangential acceleration. If the velocity of the particle is 80 ~m / s at the end of the second revolution after after motion has begun, the tangential acceleration is:

Step-by-step solution

From question aligned & r= 20 m, v=80 ~m / s & =2 revolutions =2 2 =4 rad & ^2= ₀ ^2+2 & ^2=2 ( i ) since ₀=0 & Since = a r and = V r aligned Putting these values in eq. (i) aligned & V^2 r^2 = 2 a r & a= V^2 2 r = 80 80 2 ( 20 ) 4 &=40 ~m / s ^2 aligned