In Young's double slit experiment, using monochromatic light of wavelength , the intensity of light at a point on the screen where the path difference is , is K units. The intensity of light at a point where the path difference is 3 will be :

Step-by-step solution

Phase difference is related to path difference x by = 2 x . The intensity I at a point on the screen is given by I = I_ max ^2 ( 2 ) . For x = , = 2 = 2 . Intensity I = I_ max ^2( ) = I_ max = K . For x = 3 , = 2 3 = 2 3 . Intensity I' = I_ max ^2 ( 3 ) = K ( 1 2 )^2 = K 4 . Answer: K 4