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NEET 2019
Exam
NEET
Year
2019
Subject
Physics
Chapter
Wave Optics

NEET 2019 · Physics · Wave Optics

In a double slit experiment, when light of wavelength 400nm was...

In a double slit experiment, when light of wavelength 400nm400nm was used, the angular width of the first minima formed on a screen placed 1m1m away was found to be 0.2°.0.2 ° . What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? (μwater=43)\left({\mu}_{water} = \dfrac{4}{3}\right)

Options

  1. A0.266°0.266 °
  2. B0.15°0.15 °
  3. C0.05°0.05 °
  4. D0.1°0.1 °

Correct answer

B. 0.15°0.15 °

Step-by-step solution

In air angular fringe width is given by, θ=λd\theta = \dfrac{\lambda}{d}.
Angular fringe width in water, \theta′=\thetaμ=0.243=0.15°{\text{\theta}}^{'} = \dfrac{\text{\theta}}{\mu} = \dfrac{0.2}{\dfrac{4}{3}} = 0.15 °
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