A linear aperture whose width is 0.02 cm is placed immediately in...

A linear aperture whose width is

0.02 cm

is placed immediately in front of a lens of focal length

60 cm.

The aperture is illuminated normally by a parallel beam of wavelength

5 \times {10}^{- 5}cm

. The distance of the first dark band of the diffraction pattern from the centre of the screen is A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture

A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture

Options

A $0.10\text{cm}$
B $0.25\text{cm}$
C $0.20\text{cm}$
D $0.15\text{cm}$

Correct answer

D. $0.15\text{cm}$

Step-by-step solution

By the principle of single slit diffraction pattern

$\theta = \dfrac{\lambda}{a} = \dfrac{y}{f}$
A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture
$y = \dfrac{f\lambda}{a}$ $= \dfrac{60 \times 5 \times {10}^{- 5}}{0.02} = 0.15cm$

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