At the first minimum adjacent to the central maximum of a...

At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is: $At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between$

Options

A $\dfrac{\pi}{2}$ radian
B $π$ radian
C $\dfrac{\pi}{8}$ radian
D $\dfrac{\pi}{4}$ radian

Correct answer

B. $π$ radian

Step-by-step solution

For first minima

$AP - BP = \lambda$

$At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between$

$AP - MP = \dfrac{\lambda}{2}$

So phase difference $= \dfrac{2\pi}{\lambda} \times \dfrac{\lambda}{2} = \pi$

Practice Wave Optics on Quantrex Academy →

More from Wave Optics

An unpolarized light beam of intensity I_0 passes through a series of n Polaroids P_1… MHT CET Medical 2026 In a single-slit Fraunhofer diffraction experiment, the first secondary minimum is… MHT CET Medical 2026 In the Young's double slit experiment, the intensity of light at a point on the screen is… MHT CET Medical 2026 Two images are considered "just resolved" according to Rayleigh's criterion when MHT CET Medical 2026 In Young's double slit experiment, the slits are 2\ mm apart and are illuminated by… MHT CET Medical 2026 In Young's double slit, 18 fringes are observed to be formed in a certain segment of the… MHT CET Medical 2026 When the un-polarised light beam is incident from air to glass (n = 1.5) at the… MHT CET Medical 2026 In Young's double-slit experiment, the intensity at a point is ((1)/(4)) of the maximum… MHT CET Medical 2026 Full Wave Optics list All NEET PYQs