At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is:

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Quantrex Academy · Accepted Answer

Correct answer: B. &pi; radian

For first minima A P - B P = &#955; A P - M P = &#955; 2 So phase difference = 2 &#960; &#955; &#215; &#955; 2 = &#960;

At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is:

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Correct answer

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At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen&#39;s wavelet from the edge of the slit and the wavelet from the midpoint of the slit is:

Options

Correct answer

Step-by-step solution

More from Wave Optics

At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is: