NEET 2016
- Exam
- NEET
- Year
- 2016
- Subject
- Physics
- Chapter
- Wave Optics
NEET 2016 · Physics · Wave Optics
The intensity at the maximum in a Young's double slit experiment is...
The intensity at the maximum in a Young's double slit experiment is . Distance between two slits is , where is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance ?
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
In YDSE {I}_\max = {I}_{0}
Path difference at a point in front of one of shifts is
Path difference is
So intensity at that point is
I = {I}_\max\cos^{2}\left(\dfrac{\theta}{2}\right)
Path difference at a point in front of one of shifts is
Path difference is
So intensity at that point is
I = {I}_\max\cos^{2}\left(\dfrac{\theta}{2}\right)