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NEET 2015
Exam
NEET
Year
2015
Subject
Physics
Chapter
Wave Optics

NEET 2015 · Physics · Wave Optics

In a double-slit experiment, the two slits are 1mm apart and the...

In a double-slit experiment, the two slits are 1mm1mm apart and the screen is placed 1m1m away. A monochromatic light of wavelength 500nm500nm is used. What will be the width of each slit for obtaining ten maxima of double-slit within the central maxima of a single-slit pattern?

Options

  1. A0.2mm0 . 2mm
  2. B0.1mm0 . 1mm
  3. C0.5mm0 . 5mm
  4. D0.02mm0 . 02mm

Correct answer

A. 0.2mm0 . 2mm

Step-by-step solution

d=1mm=1×10−3md = 1mm = 1 \times {10}^{- 3}m

D=1m.,λ=500×10−9mD = 1m . , \lambda = 500 \times {10}^{- 9}m

Width of the central maximum = width of 10 maxima in YDSE

2\lambdaDa=10\lambdaDd\dfrac{2\lambdaD}{a} = \dfrac{10\lambdaD}{d}

a=0.2d=0.2mma = 0.2d = 0 .2 mm
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