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NEET 2014
Exam
NEET
Year
2014
Subject
Physics
Chapter
Wave Optics

NEET 2014 · Physics · Wave Optics

In the Young’s double slit experiment the intensity of light...

In the Young’s double slit experiment the intensity of light at a point on the screen where the path difference is λ\lambda is K,K, ( λ\lambda being the wave length of light used). The intensity at a point where the path difference is λ4,\dfrac{\lambda}{4}, will be:

Options

  1. AKK
  2. BK4\dfrac{K}{4}
  3. CK2\dfrac{K}{2}
  4. DZero

Correct answer

C. K2\dfrac{K}{2}

Step-by-step solution

{I}_\max = 4{I}_{0} = K
at the other point, path difference =λ4= \dfrac{\lambda}{4}
So, phase difference ϕ=2πλ×λ4=π2ϕ = \dfrac{2\pi}{\lambda} \times \dfrac{\lambda}{4} = \dfrac{\pi}{2}
I′=I0+I0+2I0I0cosπ2{I}^{'} = {I}_{0} + {I}_{0} + 2\sqrt{{I}_{0}}\sqrt{{I}_{0}}cos \dfrac{\pi}{2}
I′=2I0=K2{I}^{'} = 2{I}_{0} = \dfrac{K}{2}
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