NEET2013PhysicsWave OpticsActual
In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits reduced to half. As a result the fringe width:
Options
- Ais halved
- Bbecomes four times
- Cremains unchanged
- Dis doubled
Correct answer
B. becomes four times
Step-by-step solution
In Young's double slit experiment fringe width = D d where D= distance between slit and screen d= distance between slit According to the question D is double 2 D and d is half d 2 Ther New fringe wilth will be 2 D d 2 = 4 D d =4 ( D d )= ^1=4 i.e., becomes four times