NEET2010PhysicsWave OpticsActual
A lens having focal length f and aperture of diameter d forms an image of intensity I . Aperture of diameter d 2 in central region of lens is covered by a black paper. Focal length of lens and intensity of image now will be respectively
Options
- Af and 1 4
- B3 f 4 and I 2
- Cf and 3 I 4
- Df 2 and I 2
Correct answer
C. f and 3 I 4
Step-by-step solution
Intensity, I A^2 I ₂ I ₁ = [ A ₂ ~A ₁ ]^2= r ^2- r ^2 4 r ^2 = 3 4 I ₂= 3 4 I ₁ and focal length remains unchanged.