AP EAMCET202315 May 2023Morning ShiftMathematicsEllipseActual
Let x^2+y^2=20 be the director circle of an ellipse E whose major axis is X -axis and minor axis is Y -axis. If the length of the latus rectum of E is 2 , then the distance between its foci is
Options
- A4 5
- B4 3
- C4 2
- D3
Correct answer
B. 4 3
Step-by-step solution
Equation of director circle ellipse is x^2+y^2=a^2+b^2 a^2+b^2=20 Given that lotus rectum = 2 b^2 a =2 b^2=a from (i) and (ii) we get a=4 We have c^2=a^2-b^2=16-4=12 c=2 3 Distance between foci =2 c=4 3 .