AP EAMCET202022 Sep 2020Evening ShiftMathematicsEllipseActual
The eccentricity of the ellipse 4 x^2+25 y^2=100 is
Options
- A21 5
- B21 2
- C21 4
- D21 25
Correct answer
A. 21 5
Step-by-step solution
4 x^2+25 y^2=100 x^2 25 + y^2 4 =1 a^2=25 and b^2=4 Ecentricity = a^2-b^2 a^2 = 25-4 25 = 21 5 Hence, option (1) is correct.