Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201921 Apr 2019Morning ShiftMathematicsEllipseActual

If the tangents drawn from a point P to the ellipse 4 x^2+9 y^2-24 x+36 y=0 are perpendicular, then the locus of P is

Options

  1. Ax^2+y^2-6 x+4 y+13=0
  2. Bx^2+y^2-6 x+4 y-13=0
  3. Cx^2+y^2=26
  4. Dx^2+y^2+6 x-4 y-13=0

Correct answer

B. x^2+y^2-6 x+4 y-13=0

Step-by-step solution

Given, equation of ellipse is aligned & 4 x^2+9 y^2-24 x+36 y=0 & 4 (x^2-6 x+9 )+9 (y^2+4 y+4 )-36-36=0 & 4(x-3)^2+9(y+2)^2=72 & (x-3)^2 18 + (y+2)^2 8 =1 aligned Here, required locus is director circle. array lrr & (x-3)^2+(y+2)^2=26 & x^2-6 x+9+y^2+4+4 y=26 & x^2+y^2-6 x+4 y=13 & x^2+y^2-6 x+4 y-13=0 array

Practice Ellipse on Quantrex Academy →

More from Ellipse

The foci of a hyperbola are the same as those of the ellipse with equation 9x^2 + 16y^2 = 144 . If the length of the transverse axis of this hyperbola is 2 , then its equation is: 2026If the two ends of the major axis of an ellipse are (5, 0) and (-5, 0) and one focus lies on the line 3x - 5y - 9 = 0 , then its equation is 2026The length of the latus rectum of the curve represented by x = 3( t + t) and y = 4( t - t) is: 2026If P be any point on the ellipse 16x^2 + 25y^2 = 400 with foci S and S' and area of PSS' is 9 square units, then the abscissa of point P is........... 2026If is the eccentric angle of a point on the ellipse x^2 25 + y^2 9 = 1 such that the distance of the point from the center is 5 , then = ....... 2026The eccentricity of the ellipse represented by the equation 7x^2 + 16y^2 - 14x + 64y - 377 = 0 is... 2026A tangent having slope - 1 2 to the ellipse 3x^2 + 4y^2 = 12 intersects the X-axis and Y-axis at the points A and B respectively. if O is the origin, then the area of AOB is ... 2026If the eccentricity of the ellipse x^2 a^2 + y^2 b^2 = 1, (a > b) is 2 3 and its focal chord is 3x + 2y - 6 = 0 , then the value of a^2 + b^2 is... 2026 Full Ellipse list All AP EAMCET PYQs