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NEST2013ChemistryCarboxylic Acid Derivatives

A sequence of reactions is shown below starting from an optically active compound P . P does not react with 2,4-dinitrophenylhydrazine (2,4-DNP) to form a hydrazone. Q reacts very rapidly with one molar equivalent of ethylamine at low temperature to form R. Select the most appropriate statement(s).

Options

  1. AQ as well as R are optically active.
  2. BQ on heating with an excess of ethylamine in the presence of a base gives a basic compound.
  3. CR is a basic compound and can react with an acid to form a salt.
  4. DAn optically inactive isomer of P on heating can form compound S ( C ₄ H ₆ O ₂ ) which does not react with thi

Correct answer

D. An optically inactive isomer of P on heating can form compound S ( C ₄ H ₆ O ₂ ) which does not react with thi

Step-by-step solution

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