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AP EAMCET201822 Apr 2018Evening ShiftMathematicsEllipseActual

The equation of the locus of a point (2 -3,3 -4) is

Options

  1. A9 x^2+4 y^2+54 x+32 y+181=0
  2. B4 x^2+9 y^2+54 x+32 y+109=0
  3. C9 x^2+4 y^2-54 x+32 y+109=0
  4. D9 x^2+4 y^2+54 x+32 y+109=0

Correct answer

D. 9 x^2+4 y^2+54 x+32 y+109=0

Step-by-step solution

Given point (2 -3,3 -4)=(x, y) Let aligned & = x+3 2 and = y+4 3 & ^2 + ^2 =1 & ( x+3 2 )^2+ ( y+4 3 )^2=1 & 9 (x^2+6 x+9 )+4 (y^2+8 y+16 )=36 & 9 x^2+4 y^2+54 x+32 y+145=36 & 9 x^2+4 y^2+54 x+32 y+109=0 aligned

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