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NEST2019ChemistryThermodynamics (C)

Consider two states, A and B , of a thermodynamic system. Let Path 1 represent a reversible process for going from A to B , while Path 2 represents an irreversible process for the same. Let the work done, heat change, and entropy change for the two processes be denoted by dw _ rev , dq _ rev , dS _ rev and dw _ irrev , dq _ irrev , dS _ irrev , respectively. It is observed that the relation dw _ rev dw _ irrev is obe

Options

  1. AdS _ irrev dS _ rev
  2. Bdq _ rev dq _ irrev
  3. Cdw _ rev + dq _ rev = dw _ irrev + dq _ irrev
  4. Ddw _ rev + dq _ rev dw _ irrev + dq _ irrev

Correct answer

C. dw _ rev + dq _ rev = dw _ irrev + dq _ irrev

Step-by-step solution

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