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AP EAMCET2015MathematicsEllipse

The radius of the circle passing through the foci of the ellipse x^2 16 + y^2 9 =1 and having its centre at (0,3) is

Options

  1. A6
  2. B4
  3. C3
  4. D2

Correct answer

B. 4

Step-by-step solution

Equation of ellipse, x^2 16 + y^2 9 =1a^2=16 a=4, b^2=9 b=3 Here, a>b Now, e= 1- b^2 a^2 = 1- 9 16 = 7 4 Focus =( a e, 0)= 7 , 0 Since, the circle passes through P ( 7 , 0) and centre at C (0,3) . aligned & Radius =r c p= (0-7)^2+(3-0)^2 & = 7+9 = 16 =4 aligned

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