NEST2017PhysicsNuclear Physics
Consider the following decay schemes: ₇₉¹⁹⁸ Au X+ ₁⁻ ₈₀¹⁹⁸ Hg + ₁ ; ₇₉¹⁹⁸ Au Y+ ₂⁻ ₈₀¹⁹⁸ Hg + ₂ ₇₉¹⁹⁹ Au X+ ₁⁻ Y+ ₃ ₈₀¹⁹⁸ Hg + ₂ The energies corresponding to X and Y with respect to ₈₀¹⁹⁸ Hg are 1.088 MeV and 0.412 MeV respectively [Note the energy of ₈₀¹⁹⁸ Hg is taken to be 0.0 MeV ]. The atomic masses of ₇₉¹⁹⁸ Au and ₈₀¹⁹⁸ Hg are 197.968 u and 197.966 u , respectively, where 1 u should be taken as 931 MeV / c ^2 .
Options
- Athe energies corresponding to ₁ and ₂ are 1.088 MeV and 0.412 MeV respectively.
- Bthe energies corresponding to ₁ and ₃ are 1.088 MeV and 0.412 MeV respectively.
- Cthe maximum kinetic energies of ₁⁻ and ₂⁻ are about 0.77 MeV and 1.45 MeV respectively.
- Dthe energy corresponding to ₇₉¹⁹⁸ Au is 1.50 MeV .
Correct answer
C. the maximum kinetic energies of ₁⁻ and ₂⁻ are about 0.77 MeV and 1.45 MeV respectively.
Step-by-step solution
No solution available.