A particle of mass m that moves along the x -axis has potential energy V(x)=a+b x^2 , where a and b are positive constants. Its initial velocity is v₀ at x=0 . It will execute simple harmonic motion. Then

Options

1. Athe acceleration of the particle at its extreme position is zero.
2. Bat its extreme position the particle will have total energy a+m v₀^2 / 2 .
3. Cits time period will be determined by the values of b and m .
4. Dthe equilibrium position of the particle is determined by a .