NEST2020PhysicsRay Optics
Consider an optical medium where refractive index varies linearly with height i.e. n(y)=n(0)+k y where k is a positive constant and y is the height above the ground level. Here positive number n(0) is the refractive index at the ground level. The refractive index at height y varies with temperature at that point as (n(y)- 1) T(y)= constant. Consider a ray propagating (in a plane) in the medium which is horizontal at
Options
- AThe temperature at height h is greater than the temperature at ground level.
- BAngle = 2 (1- n(0) n(h) ) .
- CFor n(0)=1.001 and k=1 10⁻⁴ ~m ⁻¹ , angle at height 1 meter above the ground level is equal to 1 / 5
- DAngle = 2 (1- 1 n(h) ) (1- T(h) T(0) )
Correct answer
D. Angle = 2 (1- 1 n(h) ) (1- T(h) T(0) )
Step-by-step solution
No solution available.