NTA Abhyas JEE Main2020ChemistryGeneral Principles and Processes of Isolation of MetalsPractice
Match the column (I) and (II) and select the correct answer using the codes given below. Column-I Column-II (I) Argentite (1) Halide ore (II) Cuprite (2) Carbonate ore (III) Siderite (3) Oxide ore (IV) Carnallite (4) Sulphide ore
Options
- Ai-1, ii-3, iii-4, iv-3
- Bi-3, ii-4, iii-1, iv-3
- Ci-4, ii-3, iii-2, iv-1
- Di-4, iii-2, iii-3, iv-1
Correct answer
C. i-4, ii-3, iii-2, iv-1
Step-by-step solution
Argentite  → Ag 2 S; Cuprite  → Cu 2 O Siderite → FeCO 3 ;   Carnallite → KCI ⋅ MgCI 2 ⋅ 6 H 2 O