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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Ionic Equilibrium

NTA Abhyas 2020 · Chemistry · Ionic Equilibrium

A 0.010M solution of maleic acid, a monoprotic organic acid, is 14%...

A 0.010M\text{0}\text{.010}\text{M} solution of maleic acid, a monoprotic organic acid, is \text{14%} ionized. What is Ka1{K}_{{a}_{1}} for maleic acid?A 0.010M solution of maleic acid, a monoprotic organic acid, is 14% ionized. What is K _ a _ 1 for maleic acid?

Options

  1. A2.3×10−32.3 \times 1{0}^{- 3}
  2. B2.3×10−42.3 \times 1{0}^{- 4}
  3. C2.0×10−42.0 \times 1{0}^{- 4}
  4. D2.0×10−62.0 \times 1{0}^{- 6}

Correct answer

B. 2.3×10−42.3 \times 1{0}^{- 4}

Step-by-step solution

Degree of dissociation, α=14100=0.14\alpha = \dfrac{14}{100} = 0.14

Concentration of maleic acid, C=0.010MC = 0.010\text{M}

The equilibrium reaction is

A 0.010M solution of maleic acid, a monoprotic organic acid, is 14% ionized. What is K _ a _ 1 for maleic acid?

Ka=C2α2C(1−α)=Cα2(1−α){K}_{a} = \dfrac{C^{2}{\alpha}^{2}}{C ( 1 - \alpha )} = \dfrac{C{\alpha}^{2}}{( 1 - \alpha )}

Ka=0.010×0.14×0.140.86=2.3×10−4.{K}_{a} = \dfrac{0.010 \times 0.14 \times 0.14}{0.86} = 2.3 \times 1{0}^{- 4}.
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