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The p H at the equivalent point for the titration of 0.10 M K H 2 B O 3 with 0.1 M H C l is K a of H 3 BO 3 =12 .8×10 − 10 Report your answer by rounding it up to nearest whole number.

Correct answer

5

Step-by-step solution

First there will be an acid-base reaction between K H 2 B O 3 and H C l . conc. will become half after reaction of an equal volume of K H 2 B O 3 and H C l So 0.1 5 = 0.05 Now, H + = K a C = 12.8 × 10 - 10 × 0.05 = 8 × 1 0 - 6 p H = - log ⁡ 8 × 10 - 6 ≈ 5.0

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