NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
The pH of a solution obtained by mixing equal volume of solutions having pH = 3 and pH = 4. [log 5.5 = 0.7404]
Options
- A3.26
- B3.5
- C4.0
- D3.42
Correct answer
A. 3.26
Step-by-step solution
At pH = 3 , H + = 1 0 - 3 M At pH = 4 , H + = 1 0 - 4 M When in equal volume of the two solutions are mixed, the H + = 1 0 - 3 + 1 0 - 4 2 = 1 0 - 3 1 + 0.1 2 = 1.1 2 × 1 0 - 3 H + = 5.5 × 1 0 - 4 - log H + = - log 5.5 - log1 0 - 4 pH = - 0 . 74 04 + 4 = 3 . 26