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At 277 K, degree of dissociation water is 1 × 1 0 - 7 % . The value of ionic product of water is

Options

  1. A3.0 × 1 0 - 14
  2. B3.085 × 1 0 - 15
  3. C1 × 1 0 - 16
  4. D1 × 1 0 - 14

Correct answer

B. 3.085 × 1 0 - 15

Step-by-step solution

The molar concentration of water = 1000 × 1 18 = 55.5 M α , the degree of dissociation = 1 × 1 0 - 7 100 = 1 × 1 0 - 9 K w = C α × C α or C 2 α 2 K w = ( 55.5 ) 2 ( 1 × 1 0 - 9 ) 2 = 3.085 × 1 0 - 15

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