NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
What is the minimum pH needed to prevent the precipitation of ZnS in a solution i.e. 0 .01   M   ZnCl 2 and saturated with 0 .1   M   H 2 S ? Given: K sp of ZnS   =   10 − 21 Ka of H 2 S   =   10 − 20
Correct answer
1
Step-by-step solution
K s p ( Z n S ) = [ Z n 2 + ] [ S 2 - ] S 2 - = K s p Z n 2 + = 1 0 - 21 0.01 = 1 0 - 19 K H 2 S = H + 2 S - 2 H 2 S 1 0 - 20 = H + 2 1 0 - 19 0.1 H + = 0.1 p H = - log . H + = 1