NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
Arrange in increasing order of solubility of AgBr in solutions given here (i) 0.1 M N H 3 (ii) 0.1 M A g N O 3 (iii) 0.2 M NaBr (iv) pure water
Options
- A(iii) < (ii) < (iv) < (i)
- B(iii) < (ii) < (i) < (iv)
- C(iii) < (ii) < (i) < (iv)
- D(ii) < (iii) < (iv) < (i)
Correct answer
A. (iii) < (ii) < (iv) < (i)
Step-by-step solution
AgBr → in N H 3 (Solubility increases, due to stable complex) → in 0.1 M A g N O 3 (Solubility decreases) → in 0.2 M NaBr (Solubility decreases more) → in pure water (Normal dissociation) Hence the order is (iii) < (ii) < (iv) < (i)