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What will be the pH of a solution formed by mixing 40 c m 3 of 0.1 M HCl with 10 c m 3 of 0.45 M NaOH?

Options

  1. A10
  2. B8
  3. C5
  4. D12

Correct answer

D. 12

Step-by-step solution

Number of moles of HCl = M V 1000 = 0.1 × 40 1000 = 0.004 Number of moles of NaOH = M V 1000 = 0.45 × 10 1000 = 0.0045 Remaining moles of NaOH after neutralization = 0.0045 – 0.004 = 0.0005 Molarity of O H - = 0.0005 50 × 1000 = 0.01 M So pOH = 2 So pH = 14 – 2 = 12

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