NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
The simultaneous solubility of AgCN K s p = 2.5 × 1 0 - 6 and AgCl K s p = 1.6 × 1 0 - 10 in 1 M N H 3 (aq) are respectively Given K f [ A g ( N H 3 ) 2 ] + = 1 0 7
Options
- A1.58 × 1 0 - 3 , 1.26 × 1 0 - 5
- B0.04,6.25 × 1 0 - 8
- C5.58 × 1 0 - 8 , 0.037
- D0.037,5.78 × 1 0 - 8
Correct answer
D. 0.037,5.78 × 1 0 - 8
Step-by-step solution
A g C l ( s ) + 2 N H 3 0 - 2 x ( a q ) ⇌ A g ( N H 3 ) 2 + x + C l - ( a q ) x K 1 = 1.6 × 1 0 - 10 × 1 0 7 = 1.6 × 1 0 - 3 K 1 = [ A g ( N H 3 ) 2 + [ C l - ] [ N H 3 ] 2 [ C l - ] [ C N - ] = 1.6 × 1 0 - 3 2.5 × 1 0 - 9 = 6.4 × 1 0 5 K 1 = x 2 ( 1 - 2 x ) 2 = 1.6 × 1 0 - 3 x ( 1 - 2 x ) = 0.04 x = 0.037 [ C N - ] = 0.037 6.4 × 1 0 5 = 5.78 × 1 0 - 8