NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
Acetic acid and propionic acid have K a values 1.75 × 10 - 5 and 1 .3   ×   10 − 5 respectively at a certain temperature. An equimolar solution of a mixture of the two acids is partially neutralized by NaOH. How is the ratio of the contents of acetate and propionate ions related to the K a values and the molarity ?
Options
- Aα 1 - α = 1.75 1.3 × β 1 - β , where α and β are ionized fractions of the acids
- BThe ratio is unrelated to the K a values
- CThe ratio is unrelated to the molarity
- DThe ratio is unrelated to the pH of the solution
Correct answer
A. α 1 - α = 1.75 1.3 × β 1 - β , where α and β are ionized fractions of the acids
Step-by-step solution
In a given mixture, the ionization of two acids can be written as : Let α , β be degree of ionization at same concentration. C H 3 C O O H 1 - α ⇌ C H 3 C O O - + α H + α + β C 2 H 5 C O O H 1 - β ⇌ C 2 H 5 C O O - + β H + α + β ∴   K Acetic   acid   =   α α   +   β ·c 1 − α K Propionic   acid   =   β α   +   β ⋅ c 1 − β ∴   K Acetic &#