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NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice

Three sparingly soluble salts that have same solubility products as given below I. A 2 X II. A X III. A 2 X 3 Their solubilities in a saturated solution will be such that

Options

  1. AIII > II > I
  2. BIII > I > II
  3. CII > III > I
  4. DII > I > III

Correct answer

A. III > II > I

Step-by-step solution

Let K s p = 10 - 30 10 - 30 1 2 = 10 - 15 10 - 30 4 1 3 = 10 - 10 4 1 3 10 - 30 108 1 5 = 10 - 6 108 1 5 S = K s p for AX S = K s p 4 1 / 3 for A 2 X S = K s p 108 1 / 5 for A 2 X 3 So S III > S II > S I .

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