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The pH of 0.1 M solution of a weak acid H A is 4.50. It is neutralised with certain ammount of N a O H solution to decrease the acid content to half of initial value. Calculate the pH of the resulting solution.

Correct answer

8

Step-by-step solution

p H = p K a + log ⁡ [ S a l t ] [ A c i d ] p H = p K a when weak acid is half neutralized by strong base. For weak acid = pH = 1 2 pKa − log C 4 .5 = 1 2 [pKa − log10 − 1 ] 9 − 1 = pKa ⇒ pKa = 8

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