NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
At 25 ° C the p H of a 10 – 8 M H C l solution in water is
Options
- A8
- B– 8
- Cbetween 7 and 8
- Dbetween 6 and 7
Correct answer
D. between 6 and 7
Step-by-step solution
p H of 10 – 8 M H C l will be lesser than 7 as it is acidic solution. H + = H + HCl + H + H 2 O H + = 10 − 8 + 10 − 7 ∴   H + = 1.1 × 10 − 7 pH   =   6 .96