NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
The approximate pH of a 0.1 M aqueous H 2 S solution is ( K 1 and K 2 for H 2 S are 1 × 1 0 - 7 and 1.3 × 1 0 - 13 respectively at 25 ° C)
Options
- A4
- B2
- C8
- D6
Correct answer
A. 4
Step-by-step solution
Second dissociation of H 2 S is negligible from data H 2 S ⇌ H + + H S - [ H + ] = [ H S - ] = x K 1 = [ H + ] [ H S - ] [ H 2 S ] 1 × 1 0 - 7 = x 2 0.1 So x = 1 0 - 4 p H = - log [ H + ] = - log 1 0 - 4 = 4 log 1 0 = 4 .