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If pH of a saturated solution of Ba OH 2 is 12 , the value of its K ( sp ) is found to be n × 1 0 - 7 M 3 . find the value of ‘ n ’ here?

Correct answer

5

Step-by-step solution

As pH = 12 pOH = 14 - 12 = 2 [ OH ] = 1 0 - 2 M = 0.0 1M / L In case of Ba ( OH ) 2 s ⇌ B a + 2 s + 2O H - 2 2 s As 2s = 0.0 1 m / L s = 0.01 2 = 5 × 1 0 - 3 m / L Ksp for Ba OH 2 = 4 s 3 = 4 5 × 1 0 - 3 3 = 5 × 1 0 - 7 M 3 Hence ‘ n ’ = 5

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