NTA Abhyas JEE Main2020Chemistrys Block ElementsPractice
In the following reactions, products (X) and (Y) respectively are NaOH hot and conc . + Cl 2 → (X) + side products Ca(OH) 2 dry + Cl 2 → (Y) + side products
Options
- ANaOCl and Ca ( Cl O 3 ) 2
- BNaCl O 3 and Ca ( OCl ) 2
- CNaOCl and Ca ( OCl ) 2
- DNaCl O 3 and Ca ( Cl O 3 ) 2
Correct answer
B. NaCl O 3 and Ca ( OCl ) 2
Step-by-step solution
Here the products formed (X) and (Y) are NaCl O 3 and Ca ( OCl ) 2 respectively 6 NaOH + 3 Cl 2 → 5 NaCl + NaClO 3 + 3 H 2 O 2 Ca(OH) 2 + Cl 2 → Ca(OCl) 2 + CaCl 2 + H 2 O