In the following reactions, products (X) and (Y) respectively are NaOH _ (hot and conc.) + Cl _ 2 → (X)+ side products Ca(OH) _ 2 _ (dry) + Cl _ 2 → (Y) + side products

Correct answer: B. NaCl O _ 3 and Ca ( OCl ) _ 2 Here the products formed (X) and (Y) are NaCl O _ 3 and Ca ( OCl ) _ 2 respectively 6NaOH + 3 Cl _ 2 → 5NaCl + NaClO _ 3 + 3 H _ 2 O 2 Ca(OH) _ 2 + Cl _ 2 → Ca(OCl) _ 2 + CaCl _ 2 + H _ 2 O

NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Chemistry
Chapter: s Block Elements

NTA Abhyas 2020 · Chemistry · s Block Elements

In the following reactions, products (X) and (Y) respectively are...

In the following reactions, products

\text{(X)}

and

\text{(Y)}

respectively are

\mathop{\text{NaOH}}_{\left(\text{hot and conc}\text{.}\right)} \text{+}{\text{Cl}}_{2} \to \text{(X)}\text{+}

side products

\mathop{{\text{Ca(OH)}}_{2}}_{\left(\text{dry}\right)} + {\text{Cl}}_{2} \to \text{(Y)} +

side products

Options

ANaOCl and $\text{Ca} ( \text{Cl}{\text{O}}_{3}{)}_{2}$
B $\text{NaCl}{\text{O}}_{3}$ and $\text{Ca} ( \text{OCl}{)}_{2}$
CNaOCl and $\text{Ca} ( \text{OCl}{)}_{2}$
D $\text{NaCl}{\text{O}}_{3}$ and $\text{Ca} ( \text{Cl}{\text{O}}_{3}{)}_{2}$

Correct answer

B. $\text{NaCl}{\text{O}}_{3}$ and $\text{Ca} ( \text{OCl}{)}_{2}$

Step-by-step solution

Here the products formed (X) and (Y) are

\text{NaCl}{\text{O}}_{3}

and

\text{Ca} ( \text{OCl}{)}_{2}

respectively

\text{6}\text{NaOH} + \text{3}{\text{Cl}}_{\text{2}} \to \text{5}\text{NaCl} + {\text{NaClO}}_{\text{3}} + \text{3}{\text{H}}_{\text{2}} \text{O}

\text{2}{\text{Ca(OH)}}_{\text{2}} + {\text{Cl}}_{\text{2}} \to {\text{Ca(OCl)}}_{\text{2}} + {\text{CaCl}}_{\text{2}} + {\text{H}}_{\text{2}} \text{O}

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