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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
s Block Elements

NTA Abhyas 2020 · Chemistry · s Block Elements

The first (I E _ 1 ) and second (I E _ 2 ) ionization energies...

The first (IE1)\left(I{E}_{1}\right) and second (IE2)\left(I{E}_{2}\right) ionization energies (kJ/mol) of a few elements designated by Roman numerals are given below. Which of these would be an alkali metal?

Options

  1. A
    IE1I{E}_{1} IE2I{E}_{2}
    I 2372 5251
  2. B
    IE1I{E}_{1} IE2I{E}_{2}
    II 520 7300
  3. C
    IE1I{E}_{1} IE2I{E}_{2}
    III 900 1760
  4. D
    IE1I{E}_{1} IE2I{E}_{2}
    IV 1680 3380

Correct answer

B.

IE1I{E}_{1} IE2I{E}_{2}
II 520 7300

Step-by-step solution

As alkali metals have the lowest IE1I{E}_{1} values in their respectively periods and also there is a large jump between IE1I{E}_{1} and IE2I{E}_{2} due to the removal of second electron from the noble gas core, therefore, out of the given IE1I{E}_{1} and IE2I{E}_{2} values (II) belongs to alkali metals.
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