NTA Abhyas JEE Main2020ChemistrySurface ChemistryPractice
Adsorption of a gas follows Freundlich adsorption isotherm. In the given plot, x is the mass of the gas adsorbed on mass m of the adsorbent at pressure (P). if x m ∝ P ( 1 / y ) find the magnitude of ‘ y ’ is ------.
Correct answer
2
Step-by-step solution
According to Freundlich adsorption isotherm, x m = K × P 1 / n l o g x m = l o g K + 1 n l o g P m = 1 n = 2 4 = 1 2 ⇒ n = 2 So, x m = K × P 1 / 2 Therefore, value of ' y ' is 2 .