Exam

NTA Abhyas

Year

2020

Subject

Chemistry

Chapter

Surface Chemistry

NTA Abhyas 2020 · Chemistry · Surface Chemistry

Graph between ((x)/(m))vslog P is provided for adsorption of N H _...

Graph between $\log \left(\dfrac{x}{m}\right)vslog P$ is provided for adsorption of $N{H}_{3}$ gas on metal surface. Calculate weight of $N{H}_{3}$ gas (in gm) absorbed by $24g$ of metal surface at 2 atm pressure. (Take $\log 2 = 0.3$ )

Step-by-step solution

Slope $= \dfrac{1}{n} = tan {45}^{o} = 1$
$\dfrac{x}{m} = K{P}^{\dfrac{1}{n}}$
$\log \left(\dfrac{x}{m}\right) = log K + \dfrac{1}{n}log P$
$= \log 2 + \dfrac{1}{n}\log 2$
$\log \left(\dfrac{x}{m}\right) = \log 2 + \left(1\right)\log \left(2\right)$
$\dfrac{x}{m} = 2 \times 2$
$\dfrac{x}{24} = 4$
$\text{x} = 4 \times 24 = 96\text{g}$