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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Surface Chemistry

NTA Abhyas 2020 · Chemistry · Surface Chemistry

10 mL of 1 mM surfactant solution forms a monolayer covering 0. 24...

10 mL of 1 mM surfactant solution forms a monolayer covering 0. \text{24 c}{\textm^{2} on a polar substrate. If the polar head is approximated as cube, what is its edge length?

Options

  1. A2.0 pm
  2. B2.0 nm
  3. C1.0 pm
  4. D0.1 nm

Correct answer

A. 2.0 pm

Step-by-step solution

Millimoles =10×10−3=10−2= 10 \times 1{0}^{- 3} = 1{0}^{- 2}

Moles =10−5= 1{0}^{- 5}

No. of molecules =6×1023×10−5=6×1018= 6 \times 1{0}^{23} \times 1{0}^{- 5} = 6 \times 1{0}^{18}

Surface area ocupied by one molecule

= \dfrac{0.24}{6 \times 1{0}^{18}} = 0.04 \times 1{0}^{- 18}\text{c}{\textm^{2}

4×10−20=x2[∵x=4 \times 1{0}^{- 20} = x^{2} [ ∵ x = edge length ]]

x=2×10−10x = 2 \times 1{0}^{- 10} cm =2= 2 pm
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