Plot of log x/m against log p is a straight line inclined at an angle of 45 ° . When the pressure is 0.5 atm and Freundlich parameter, k is 10, the amount of soluble adsorbed per gram of adsorbent will be ( 5 = 0.6990)

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Correct answer: 5

According to Freundlich equation ((x)/(m)) = k p ^ (1)/(n) ((x)/(m)) = log k + (1)/(n)log p So plot of log x/m vs log p is linear wit slope = 1/n and intercept = log k. Thus (1)/(n) = tan θ = 45 ° = 1 or n = 1 At p = 0.5 atm and k = 10 (x)/(m) = 10 × ( 0.5 ) ^ 1 = 5 so x = 5 g

Plot of log x/m against log p is a straight line inclined at an...

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