Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020MathematicsArea Under CurvesPractice

The area bounded by the curve y 2 = 1 - x and the lines y = x x , x = - 1 and x = 1 2 is

Options

  1. A3 2 - 11 6 s q . u n i t s
  2. B3 2 - 11 4 s q . u n i t s
  3. C6 2 - 11 5 s q . u n i t s
  4. DNone of these

Correct answer

A. 3 2 - 11 6 s q . u n i t s

Step-by-step solution

From the diagram, the area of the shaded region, A = ∫ - 1 0 - 1 - - 1 - x d x + ∫ 0 1 2 1 - 1 - x d x = - x - 1 - x 3 2 3 2 - 1 0 + x + 1 - x 3 2 3 2 0 1 2 = - 2 3 - 1 - 2 × 2 3 2 3 + 1 2 + 2 3 × 2 3 2 - 2 3 = 2 3 × 2 3 2 + 2 × 2 3 2 3 - 4 3 - 1 2 = 3 2 - 4 3 - 1 2 = 3 2 - 11 6 s q . u n i t s

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the curve C₁ given by y = e^ -x for x [0, 10 ] , and the curve C₂ given by y = e^ -x ( x + x) for x [0, 10 ] . Let n be the total number of points of intersection 2026Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If is the area of the common region that lies inside both the given ellipses, then the value o 2026The area of the region (x, y) : x^2 - 8x y -x is : 2026The area of the region (x, y) : 0 y 6 - x, y^2 4x - 3, x 0 is: 2026The area of the region R = (x, y): xy 27, 1 y x^2 is equal to: 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: 2026The area of the region (x, y): y - |x|, y |x x|, y 0 is: 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A + 6 _e(3)) is equal to _______. 2026 Full Area Under Curves list All NTA Abhyas JEE Main PYQs