NTA Abhyas JEE Main2020MathematicsArea Under CurvesPractice
The area (in sq. units) enclosed between the curve x = 1 - t 2 1 + t 2 ,   y = 2 t 1 + t 2 ,   ∀ t ∈ R and the line y = x + 1 above the line is
Options
- Aπ 4
- B1 2
- C3 π 4 + 1 2
- Dπ 4 - 1 2
Correct answer
D. π 4 - 1 2
Step-by-step solution
Let, t = tan ⁡ θ ⇒ x = cos ⁡ 2 θ ,   y = sin ⁡ 2 θ ⇒ x 2 + y 2 = 1 Area of the shaded region = π 4 - 1 2 × 1 × 1 = π 4 - 1 2 sq. units